6x-2y=10 and 6x+3y=15

x = 2 ; y =1

Step-by-step explanation:

6x-2y=10  (i)

6x+3y=15  (ii)

multiply (i) by (-1)

(i)* (-1)      -6x + 2y = -10

(ii)              6x + 3y = 15

add,                  5y = 5

                           y= 5/5

                          y = 1

Put y = 1 in (i)

              6x - 2*1 = 10

                6x - 2  = 10

                      6x = 10 + 2

                      6x = 12

                       x = 12/6

x = 2

x = 2 , y = 1

Step-by-step explanation:

to solve this simultaneous equation, we say

let

6x - 2y = 10 equation 1

6x + 3y = 15 equation 2

using substitution method

from equation 1

6x - 2y = 10 equation 1

6x = 10 + 2y

divide both sides by 6

x  = (10 + 2y)/6 equation 3

put the value of x in equation 2

6x + 3y = 15 equation 2

6[( 10 + 2y)/6] + 3y = 15

10 + 2y + 3y = 15

collect the like terms

2y + 3y = 15 - 10

5y = 5

divide both sides by 5

we have

y = 1

put y = 1 in equation 3 to get the value of x

x  = (10 + 2y)/6 equation 3

x = 10 + 2(1) /6

x = 12/6

x = 2

therefore the value of x and y is 2 & 1 respectively

answer: the answer is 35%

-1   1/6.   you dont subtract the denominators

step-by-step explanation: