A researcher asks participants to estimate the calories they consume in a meal. The researcher records the following estimates: 450, 426, 310, 500, and 220. If the researcher removes the estimate of 220 (perhaps because the participant drops out of the study), then the value of the mean will:

Increase

Step-by-step explanation:

The researcher records the following estimates: 450, 426, 310, 500, and 220.

The mean of these estimates is derived below.

Mean = (450+426+310+500+220)/5

=1906/5=381.2

If the researcher removes the estimate of 220.

The mean of the other numbers will be:

Mean =(450+426+310+500)/4

=1686/4=421.5

By comparison of the two mean, we can see that the value of the mean will increase.

i believe the answer is letter c) 8

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204