A factory can work its employees no more than 5 days a week, and no less than 2 days per
week. Create an inequality to represent the range of days an employee can work. Solve the
inequality to determine the range in hours. Show all of your work and explain each of your
steps. Explain your answer.

Yes she is correct. when you do 1/5 the tbe is their to represent the fraction. so yes, kathy got it

It might be "an artistic taste"  hope i !

6x - 3y = by 2-2x + 6y = 1412x - 6y = 6 (result of multiplying by 2)-2x + 6y = 1410x = 20x = 20/10x = 26x - 3y = 36(2) - 3y = 312 - 3y = 3-3y = 3 - 12-3y = - 9y = -9/-3y = 3solution is (2,3) < ==

F(x) =2.96.(1.04)ˣ, where x is the number of monthsprice at the origin, when x = 0→ f(x) = 2.96(1.04)⁰  →f(x) = 2.96(remember any number with exponent 0 gives 1).price after 1 month (x=1)  → f(x) =2.96.(1.04)¹ = 3.0784increase of cost = (3.0784-.96)/2.96 = 0.04 or 4% increase.however you could have noticed it from the formula: f(x) =2.96.(1.04)ˣ = 2.96(1+0.04)ˣ (and the 0.04 or 4% is the increase over 1.sorry for the 2nd part, i am confused with your "table" . i have to see a proper table in order to you