Your town is building a circular ice rink with a diameter of 100 feet. Around the ice rink will be a walkway that is 10 feet wide. What is the approximate area of the walkway?

The area of the walkway is 3,454 square ft

Step-by-step explanation: The diameter of the ice rink is given as 100 ft, which makes the radius 50 ft (radius = diameter/2, i.e 100/2 = 50).

Hence the area of the ice rink would be

Area of a circle = pi x radius^2

Area of a circle = 3.14 x 50^2

Area of a circle = 7850

The area of the ice rink is 7,850 square ft.

The walkway around the ice rink is 10 ft wide. So the radius of the ice rink plus the walkway is derived as 50 plus 10, which equals 60 ft. Hence the area all around the ice rink including the walkway is now,

Area = pi x radius^2

Area = 3.14 x 60^2

Area = 11304 square ft

The area of the walkway is now given as;

Area = 11304 - 7850

Area = 3454

Therefore the area of the walkway around the ice rink is 3,454 square ft

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2