Find the area of the shaded region.
60
5 cm
A ~ [?] cm2
iter a decimal rounded to the nearest tenth

76.3 cm^2 to the nearest tenth.

Step-by-step explanation:

The area of the clear segment

= area of the sector - area of the triangle

=  1/6π r^2 - area of the triangle.

If we halve the equilateral triangle we have a 30-6-90 triangle whose height  is 5 *  5*√3/2.

Area of the triangle = 1/2 base * height

= 1/2 * 5 * 5*√3/2

Area of the segment

= 1/6 * π 5^2 -  12.5 * √3/2

= 2.265 cm^2.

So the area of the shaded part

=   π 5^2 - 2.265

= 76.27 cm^2.

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value