You are taking a multiple-choice test that has 7 questions. Each of the questions has 5 choices, with one correct choice per question. If you select one of these options per question and leave nothing blank, in how many ways can you answer the questions?

78,125 ways

Step-by-step explanation:

Since each question has 5 answer options, then each question has 5 ways to answer it, therefore, for each question it would be:

1st question: 5 ways to answer yourself

2nd question: 5 ways to answer yourself

.

.

.

7th question: 5 ways to answer yourself

All the ways would be the total of the multiplication of each question, that is, 5 ^ 7, since there are 7 questions.

5 ^ 7 = 78125

There would be a total of 78,125 ways to answer the exam.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: