Help ASAP: Find the length of RT

First answer and correct answer gets

PICTURE IS CLEAR - ZOOM IN

32

Step-by-step explanation:

the equation of a right triangle is x^2 + y^2 = z^2, where x and y are the legs and z is the hypotenuse

write the equations for triangles QTS and STR:

RT^2 + TS^2 = 40^2

7^2 + TS^2 = 25^2

then solve for RT:

RT^2 - 7^2 = 40^2 - 25^2 (subtract second equation from first)

RT^2 = 1024

RT = 32

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0