In the figure, ABCDE is a pentagon with BE||CD and BCIDE. BC is perpendicular to
CD. AB= 5cm, AE=5cm, BE= 7cm, BC= x-y and CD= x+y. If the perimeter of ABCDE is
27cm. find the value of x and y. given x, y 0.

BC=DE= x-y

AB+BC+CD+DE=5+x-y+x+y+x-y=27 cm

5+3x-y=27 cm

3x-y=22

if x=9 , then 3*9-y=22,  27-y=22, y=27-22, y=5

Step-by-step explanation:

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right