What is the equation of the line represented by the table below? Х-2,-1,0,1,2 y16,11,6,1,-4

y = -5x + 6

Step-by-step explanation:

General equation of a line : y = mx + cwhere c is intercept

To find m pick any two points..

(-2, 16) and (-1, 11)

Using (y - y¹) / (x - x¹)

(11 - 16) / (-1 - [-2]) = -5 / 1

= -5

To find c sub with any point for (x, y) and m

using (2, -4)

y = mx + c

-4 = -5(2) + c

-4 = -10 + c

6 = c

Input the values of m and c in the general equation without x and y

; y = -5x + 6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐