Consider n independent flips of a coin having a probability p of landing on heads. Say that a changeover occurs whenever an outcome differs from the one preceding it. For instance, if n = 5 and the sequence of tosses is HHTHT, then there are three changeovers at tosses 3,4, and 5. Find the expected number of changeovers in n tosses.

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

it shoild be o

step-by-step explanation: