Cans of soda vary slightly in weight. Given below are the measured weights of seven cans, in pounds. Find the mean and median of these weights. Which, if any, of these weights would be considered an outlier? What are the mean and median weights if the outlier is excluded?

0.8161 0.8195 0.8163 0.8177 0.7913 0.8141 0.8125

first mean is 0.8125

Median is 0.8161

Outlier is 0.7913

Second mean is 0.816

Second median is 0.8162

Step-by-step explanation:

Mean =( summation of weights)/number of object

Mean = (0.7913+0.8125+0.8141+0.8161+0.8163+0.8177+0.8195)/(7)

= 5.6875/7

=0.8125

Median if arranged ascending order

0.7913,0.8125,0.8141,0.8161,0.8163,0.8177,0.8195 is

=0.8161

The weight to be considered an outlier is 0.7913 because all others are between the range of 0.81

Mean if outlier is removed

Mean= (0.8125+0.8141+0.8161+0.8163+0.8177+0.8195)/(6)

= 4.8962/6

=0.816

Median if arranged ascending order

0.8125,0.8141,0.8161,0.8163,0.8177,0.8195 is

=(0.8161+0.8163)/2

=1.6324/2

= 0.8162

19.side- angle- side

20. angle- side- angle

step-by-step explanation: