The radius of the base of a cylinder is increasing at a rate of 777 millimeters per hour. The height of the cylinder is fixed at 1.51.51, point, 5 millimeters. At a certain instant, the radius is 121212 millimeters. What is the rate of change of the volume of the cylinder at that instant (in cubic millimeters per hour)

252π  or 791.7 mm³/h

Step-by-step explanation:

The volume of a cylinder is given by

We desire to find the volume rate, that is,

dr/dt is the rate of change of the radius which is 7 mm/h.

dV/dr is derived by differentiating the volume equation, yielding

At r = 12 mm and h = 1.5 mm,

answer: 2/4

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column