An independent-measures study produces sample means of M 1 = 20 and M 2 = 17. If both samples have n = 18 scores and Cohen’s d = 0.50, what is the value for the pooled variance?

Pooled variance =6

Step-by-step explanation:

Cohen's d is usually used in metal analysis. The formular for Cohen's d is given by:

Cohen's d= mean difference/ pooled variance.

Mathematically, it is written as:

Cohen's d =( M1 - M2) / S^2p

Where M1= mean for group 1

M2= mean for group 2

S^2p = pooled variance

Given:

M1= 20 , M2 = 17 and Cohen's d = 0.50

Pooled variance = ( M1 - M2)/ Cohen's d

Pooled variance = (20 - 17 ) / 0.5 = 3/0.5

Pooled variance = 6

do your own work and don"t cheat.

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b