A circle with center c(4,-2) contains the point D(8,1). what is the equation of the line perpendicular to the radius of the circle passing through point c?

Step-by-step explanation:

slope of CD=(1+2)/(8-4)=3/4

slope of line ⊥ to CD=-4/3

eq. of line with slope -4/3 and passing through (4,-2) is

y-y1=m(x-x1)

y+2=-4/3(x-4)

3y+6=-4x+16

3y=-4x+16-6

3y=-4x+10

or 4x+3y-10=0

this is the eq. of line in the form  ax+by+c=0

or in slope form

y=-4/3 x- 10/3

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