A ball has been thrown into the air its distance from the ground is given by the function s(t)=-16t^2+96t+100
where t is measured in seconds and s is measured in feet. At what time the velocity change from positive to negative {} seconds.

For t=3 sec the velocity change from positive to negative

Step-by-step explanation:

we have

This is the equation of a vertical parabola open downward (the leading coefficient is negative)

where

s(t) is the distance in feet

t is the time in seconds

We know that

To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation

The turning point of the quadratic equation is the vertex

so

Convert the quadratic equation into vertex form

Factor -16

Complete the square

Rewrite as perfect squares

The vertex is the point (3,244)

therefore

For t=3 sec the velocity change from positive to negative

da freeck kinda math is this just drop out

step-by-step explanation:

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two