What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4= (x-6) and passes through the point (-2,-2)?

A) y=-2/3x-10/3
B) y=-2/3x+10/3
C) y=3/2x-1
B) y=3/2x+1

y = -x - 4

Step-by-step explanation:

Compare the given y-4= +1(x-6) to y - k = m(x - h), where (h, k) is a point on that line.  We then know immediately that the slope of the given line is -1/1, or m = -1.  

A line perpendicular to this given line that also passes through (-2, -2) is then:

y + 2 = -1(x + 2), or y + 2 = -x - 2, or y = -x - 4

560

step-by-step explanation:

giggidy

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b