Mathematics, 12.03.2020 18:31 filzaf9632
From the previous step we have erx(6r2 + 3r − 3) = 0. Since erx is never 0, then we know 6r2 + 3r − 3 = 0. Solving the above equation gives the solutions to the quadratic equation.
Answers: 3
Mathematics, 21.06.2019 14:00
Tracy solved the following problem. which of the statements is true? 9 ÷ 3 + 6 × 2 3 + 6 × 2 9 × 2 18 her answer is correct. her answer is incorrect. she should have multiplied before dividing. her answer is incorrect. she should have multiplied before adding. her answer is incorrect. she should have added before dividing.
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Mathematics, 21.06.2019 17:00
What properties allow transformation to be used as a problem solving tool
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Mathematics, 21.06.2019 22:10
In which direction does the left side of the graph of this function point? f(x) = 3x3 - x2 + 4x - 2
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From the previous step we have erx(6r2 + 3r − 3) = 0. Since erx is never 0, then we know 6r2 + 3r −...
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