Macaws are tropical birds that can live a very long time. The box plots below show the life spans (in years) of a random sample of Macaws that lived in captivity and a random sample that lived in the wild. Which pieces of information can be gathered from these box plots? Choose all answers that apply: Choose all answers that apply: (Choice A) A On average, life spans were longer for the Macaws in the wild. (Choice B) B The life spans for all of the Macaws in captivity were longer than all of those in the wild. (Choice C) C The life spans for the Macaws in the wild varied noticeably more than those in captivity. (Choice D) D None of the above 2 horizontal boxplots titled Captivity and Wild are graphed on the same horizontal axis, labeled Life Span, in years. The boxplot, titled Captivity, has a left whisker which extends from 66 to 73. The box extends from 73 to 80 and is divided into 2 parts by a vertical line segment at 77. The right whisker extends from 80 to 84. The second boxplot, titled Wild, has a left whisker which extends from 32 to 48. The box extends from 48 to 62 and is divided into 2 parts by a vertical line segment at 54. The right whisker extends from 62 to 77. All values estimated.

The wider boxplot and longer whiskers for the Macaws in the wild show that there is a higher range and standard deviation, which points to less consistency and higher variability. You can think of it like shooting a bow and arrow. The more accurate and consistent shots are in a narrow range, while the more inconsistent are in a wider range.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation:

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