Tom wants to buy a pizza. He can select from 5 different sizes, 4 types of crust, and 12 toppings for his pizza. How many different possible outcomes of 1 size, 1 crust, and 1 pizza topping Tom can buy

240

Step-by-step explanation:

Tom have 5 possibles sizes * 4 possibles types of crust *12 possibles toppings.

If you multiply all the possiblilities you will find the

5*4*12=240

The number of different possible outcomes of 1 size, 1 crust and 1 pizza topping that Tom can buy from 5 sizes, 4 types of crust and 12 pizza toppings is 240 OUTCOMES OR SELECTIONS

Step-by-step explanation:

Since Tom can select 1 size from 5 different sizes,

he can select 1 type of crust from 4 types

he can select 1 pizza topping from 12 pizza toppings;

We can obtain the number of different possible outcomes of 1 size, 1 crust and 1 topping that Tom can buy by multiplying the different combinations of sizes, types and toppings.

Now, if he can select one size from 5 sizes, the combination will be;

5c1 = (5p1)/1!

= 5!/[(5-1)1!]

= 5*4*3*2*1/[(4*3*2*1)*1]

= 120/24

= 5

If he can select one crust type from 4 available types, the combination will be=

4c1 = 4P1/1!

= 4!/(4-1)!

= 4!/3!

= 4

If Tom can also select one pizza topping from 12 pizza toppings, the combination will be =

12c = 12p1/1!

= 12!/(12-1)!

= 12!/11!

= 12

Multiplying the different combinations to determine the number of different possible outcomes of 1 size, 1 crust and 1 pizza topping that Tom can buy:

= 5c1 × 4c1 × 12c1

= 5 × 4 × 12

= 240 selections

not solvable

step-by-step explanation:

we need more information, or at least an

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.