In a test,
Section A has 80 marks
Section B has 120 marks
Riya scores
55% in Section A
70% in Section B.
To pass, Riya needs to score 65% of the total marks.
Does she pass?
You must show your working.

Riya fails in the exam by 2 marks.

Step-by-step explanation:

Total marks in Section A = 80 marks

Total marks in Section B = 120 marks

Total marks in the test = 120 + 80 = 200 marks

Percentage required to pass = 65%

⇒ Required marks to pass = 65% of 200 = 65/100 × 200 = 130 marks

Marks scored in Section A = 55% = 55% of 80 = 55/100 × 80 = 44 marks

Marks scored in Section B = 70% = 70% of 120 = 70/100 × 120 = 84 marks

Total marks scored = 44 + 84 = 128 marks

128 < 130 ⇒ Riya fails in the test.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!