Cars arrive at a toll booth according to a Poisson process with mean 70 cars per hour. Suppose the attendant makes a phone call. How long, in seconds, can the attendant's phone call last if the probability is at least 0.5 that no cars arrive during the call

35.6 seconds

Step-by-step explanation:

The Poisson distribution has a probability model that follows the given relationship:

For x = zero calls at a probability of 50%, the arrival rate during the call is:

Since cars arrive at a rate of 70 per hour, the length of call 'n' in seconds is:

The call should be at most 35.6 seconds long to ensure a 50% probability that no cars arrive during the call.

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.