If the radius of curvature of the convex side is 8.00 cm, find the magnitude of the radius of curvature of the concave side such that the lens will be diverging with a focal length equal to -16.4 cm. The lens is made of glass with an index of refraction equal to 1.58.

Step-by-step explanation:

As we  know, the focal length equal to -16.4 cm

<=> =  -16.4

<=> P(lens) = -5/82

But the formular of The Lens Maker is:

P(lens) = (n-1) ( - ) where:

<=>-5/82 = (1.58-1) ( - )

<=> = 4.345 cm

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.