Suppose that E and F are two events and that Upper N (Upper E and Upper F )equals480 and Upper N (Upper E )equals970. What is Upper P (F|E )?

P(F|E) is 0.494 (49.4%)

Step-by-step explanation:

according to Bayes's theorem

P(F|E) = P(F∩E)/P(E) = (N(F∩E)/total number of elements) /( N(E)/total number of elements )= N(F∩E)/N(E)

replacing values

P(F|E) = N(F∩E)/N(E) = 480/970 = 0.494 (49.4%)

thus P(F|E) (probability that F occurs given that E has occurred ) is 0.494 (49.4%)

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.