Suppose that both the radius r and height h of a circular cone are increasing at a rate of 7 cm/s. How fast is the volume of the cone increasing when r=15 cm and h=10 cm?

The volume of the cone is increasing at the rate oof 3848.45 cm³/s when r=15 cm and h=10 cm.

Step-by-step explanation:

The volume of the cone is given by the following formula:

In which V is measured in cm³ while r and h are measured in cm.

Suppose that both the radius r and height h of a circular cone are increasing at a rate of 7 cm/s.

This means that

How fast is the volume of the cone increasing when r=15 cm and h=10 cm?

This is when .

Applying implicit differentiation:

We have three variables, V, r and h. So

The volume of the cone is increasing at the rate oof 3848.45 cm³/s when r=15 cm and h=10 cm.

1; 35 is the ratio

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet