The sum of two numbers is 157. one number is 101 more than the other find the numbers ?

a = 129 and b = 28

Step-by-step explanation:

solution ,

here ,

Given , the sum of two numbers is 157 and

one number is 101 more than other

So , let's assume the two numbers be a and b

According to the question ,

a+b=157¡

Again,

a = 101 + b

or,a - b = 101 ¡¡

Adding both equation's

a + b = 157

+ a - b = 101

2a = 258

or, a = 258/ 2

or, a = 129

So, keeping the value of a in equation ¡

a + b = 157

or, 129 + b = 157

or, b = 157-129

or, b = 28

so the required number is 28 and 129

c

step-by-step explanation:

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90