Consider the line y=-7x+7
Find the equation of the line that is parallel to this line and passes through the point (2, 5)
Find the equation of the line that is perpendicular to this line and passes through the point (2, 5)

y = -7x + 19 parallel

7y = x + 33 perpendicular

Step-by-step explanation:

Parallel line:

y = -7x + c

5 = -7(2) + c

c = 19

y = -7x + 19

Perpendicular line:

y = (1/7)x + c

5 = (1/7)(2) + c

c = 5 - 2/7 = 33/7

y = (1/7)x + (33/7)

7y = x + 33

25

step-by-step explanation:

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer