You are building a rectangular planter for your school garden. You want the area of the planter to be 90ft. You want the length of the planter to be 3ft longer than twice it's width. What should the dimensions of the bottom of the planter be?

length = 15 ft

Width = 6 ft

Step-by-step explanation:

Let L represent the length of the rectangular planter.

Let W represent the width of the rectangular planter.

You want the area of the planter to be 90ft. It means that

LW = 90- - - - - - - - - -1

You want the length of the planter to be 3ft longer than twice its width. It means that

L = 2W + 3

Substituting L = 2W + 3 into equation 1, it becomes

W(2W + 3) = 90

2W² + 3W = 90

2W² + 3W - 90 = 0

2W² + 15W - 12W - 90 = 0

W(2W + 15) - 6(2W + 15) = 0

W - 6 = 0 or 2W + 15 = 0

W = 6 or W = - 15/2

Since the width cannot be negative, then W = 6

L = 2W + 3 = 2 × 6 + 3

L = 12 + 3

L = 15

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225