The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for pi

18.86 feet

Step-by-step explanation:

The formula for determining the circumference of a circle is expressed as

Circumference = πD

Where D represents the diameter of the circle.

The circumference of the inner circle is 44 ft. It means that

22/7 × D = 44

22D = 7 × 44 = 308

D = 308/22

D = 14 ft

The distance between the inner circle and the outer circle is 3 ft. This means that the diameter of the outer circle would be

14 + 3 + 3 = 20 ft

Circumference of the outer circle is

22/7 × 20 = 62.86 ft

The number of feet by which the circumference of outer circle is greater than the circumference of the inner circle is

62.86 - 44 = 18.86 feet

the correct is answer is a 9-sided polygon!