Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?

a No, the remainder is 0, so x-5 is not a factor of P(x)

b Yes, the remainder is 0, so x-5 is a factor of P(x)

c Yes, the remainder is -240, so x-5 is a factor of P(x)

d No, the remainder is -240, so x-5 is not a factor of P(x)

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

Step 1:  Factor

p(x) = x^3 - 5x^2 - x + 5

p(x) = (x - 5)(x + 1)(x - 1)

Yes, the remainder is 0 so, x-5 is a factor of p(x)

 Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11