A rectangle has a length that is nine feet less than four times it's width it's area is 90 square feet algebraiclly determine the length of its width and length

Length of the rectangle is 15 feet and width of the rectangle is 9 feet.

Step-by-step explanation:

Given:

Area of the rectangle = 90 square feet

We need to find the length and width of the rectangle.

Solution:

Let the width of the rectangle be denoted by 'w'.

Now given:

length is nine feet less than four times it's width.

so we can say that;

length of the rectangle =

Now we know that;

Area of the rectangle is given by length times width.

framing in equation form we get;

Now we will factorize so as to find the roots.

Now substituting separately we will find 2 value of w.

Now we get 2 value of w one positive and one negative and we know that width of the rectangle can't be negative hence we will discard negative value  and consider positive value.

width of the rectangle = 6 ft

Length of the rectangle =

Hence Length of the rectangle is 15 feet and width of the rectangle is 9 feet.

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )