In a lab experiment, 60 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 21 hours. How long would it be, to the nearest tenth of an hour, until there are 107 bacteria present?

What your looking for is an exponential growth or population growth formula, which is:

For this specific question you're trying to solve 'x' for this equation:

(x/21 has been used as this formula usually deals with 1 hour/day/etc periods not 21 or other numbers)

If you put that formula into a calc to solve for x (e.g. symbolab) then you get the time for the population growth (right side) to equal the desired population amount (left)

Therefore, the time it take the bacteria to reach 107 is 17.526hrs

each side has a different length.  

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it