Which of the following is a foci of x2/16-y2/4 ? (2√5, 0) (0, 2√5) (2√3, 0)

foci of is . correct option a.

Step-by-step explanation:

Complete equation of Hyperbola for the above question is x2/16-y2/4  = 1 or  , Simplify each term in the equation in order to set the right side equal to  1 . The standard form of an ellipse or hyperbola requires the right side of the equation be  1 . This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola:

a=4 , b = 2, h = 0 , k= 0

Find the distance from the center to a focus of the hyperbola by using the following formula:

Substitute the value of  a  and  b  in the formula.

=

The first focus of a hyperbola can be found by adding  c  to  h

(h+c,k)

Substitute the known values of h ,  c , and  k into the formula and simplify:

. ∴ foci of is . correct option a.

(2√5, 0)

Step-by-step explanation: got it right

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0