If function fhas zeros at -3 and 4graph could represent function 1

All the graph in attachment ate possible solutions.

Step-by-step explanation:

The graph that has zeros at -3 and 4, will intersect the x-axis at x=-3 and x=4.

The function could be a parabola that opens up or down and intersects the x-axis at x=-3 and x=4.

It could also be a fourth degree polynomial.

See attachment

12*c

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.