A circle with radius 9 has a sector with a central angle of 120 degrees. What is the area of the sector?

Step-by-step explanation:

January 15, 2012 4:31PM

I assume you want the area of the sector with angle 120o and radius 9 cm:

120o is 120/360 = 1/3 of a full circle.⇒ area of sector is 1/3 area of full circle

⇒ area_of_sector = 1/3 x π x radius2 = 1/3 x π x (9 cm)2

= 27π cm2

≈ 84.82 cm2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

6 and 24

step-by-step explanation:

6 x 4 = 24