If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?
Х

(f+g) (x) =0 for x=-2

Step-by-step explanation:

f(x) = x^2 – 2x, g(x) = 6x + 4,

(f+g) (x) =f(x) +g(x) =

(x^2 – 2x) + (6x + 4) =

x^2 – 2x+ 6x + 4=

x^2 +4x+4

(f+g)(x) =x^2 +4x+4=0 (quvadratic equation)

x^2 +4x+4=x^2 +2x*2+2^2=(x+2)^2

then

(x+2)^2 =0

x+2=0

x=-2

(f+g) (x) =0 for x=-2

20days louise can read300 pg

step-by-step explanation:

1 day 15 pg 300: 15= 20

x day 300 pg

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: