Let D be a region bounded by a simple closed path C in the xy-plane. The coordinates of the centroid x, y of D are x = 1 2A x2 dy C y = − 1 2A y2 dx C where A is the area of D. Find the centroid of a quarter-circular region of radius a.

The centroid is the same as the center of mass when the density ρ is constant.the density cancels in the center of mass formula, and it becomes this formula for the centroid.

This can be interpreted as saying the coordinates of the centroid are the mean, or average values of x  and y on D. So we now have a double integral formula for (¯x, y¯) and a suggestion in the problem that the centroid can also be computed from line integrals on the boundary using Green’s theorem. So we just plug in Green’s theorem into these line integrals to convert them to double integrals and see what we get.

for the integral  

we have

then by Green's theorem

in the same way we find

And that is all that the problem asks. Note that the area A is also a double integral that can be  converted by Green’s theorem to a line integral over C.  it is just assumed that one way or another the area is computed and given the name A.

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

i can't read the graph

step-by-step explanation: