A father is 43 years old and his 2 children is 8 and 6 years old. how many years will the sum of the ages of the two children be until they're twice the father's age? I NEED ANSWER ASAP

5 years

Step-by-step explanation:

43 + x = 2(8 + x + 6 + x)

43 + x = 2(14 + 2x)

43 + x = 28 + 4x

3x = 15

x = 5

Note: your English is not correct, therefore the question is invalid.

I believe the question should be something like this:

A father is 43 years old and his 2 children are 8 and 6 years old. How many years will pass until the sum of the ages of the two children will be exactly a half of their father's age?

In 5 years, since 13 + 11 = 24 > half of 48

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.