(1 point) Urn A has 5 white and 17 red balls. Urn B has 9 white and 12 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed heads

The probability that the coin landed heads is 65.3%.

Step-by-step explanation:

Given : Urn A has 5 white and 17 red balls. Urn B has 9 white and 12 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected.

To find : What is the probability that the coin landed heads ?

Solution :

Let the event A be the ball taken from Urn A (5 white and 17 red balls)

Let B=A'- the ball taken from urn B(9 white and 12 red balls)

Let W be event that a white ball is selected.

An urn is chosen based on a toss of a fair coin.

P(A) = coin landed on heads =

P(B) = coin landed on tails =

and

Using Bayes formula,

Therefore, the probability that the coin landed heads is 65.3%.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: