A 1300 kg car with the brakes applied comes to a stop in 6.10 s. During
these 6.10 s the force of friction slowing down the car is 2200 N. What is
the change in momentum of the car?

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

something over 10 so ? /10

step-by-step explanation:

if you are looking for the unit rate then the answer would be 9 because unit rate is distance divided by time.

step-by-step explanation: