Find the value of c that makes each trinomial a perfect square
x^2-19x+c
Please Help! :)

The value of c is

Explanation:

Given that the trinomial is

We need to determine the value of c such that the trinomial is a perfect square.

The value of c can be determined using the formula,

From the trinomial, the value of b is given by

Substituting the value of b in the above formula, we have,

Squaring both the numerator and denominator, we have,

Thus, the value of c is which makes the trinomial a perfect square.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°