Write an equation of the line that is perpendicular to the line y =
1
3
x + 6 that passes through the point (2,-3).

A) y = 3x + 9
B) y = -3x - 3
C) y = -3x + 3
D) y =
1
3
x + 9

c) y= -3x + 3

Step-by-step explanation:

Given equation

y= 1/3x+6

Here slope m1 = 1/3

We know that the slope of perpendicular lines

m1*m2 = -1

slope of perpendicular line m2 = -1/m1

                                                    = -1/ (1/3)

                                              m2 =  -3

Also the line passes through (2, -3)

equation of line is given by y = mx+b

y= -3

x=  2

m2 = -3

Applying above values to the equation of line,

-3 = (-3*2)+b

b=3

Hence equation of perpendicular line is y = -3x + 3

b i think

step-by-step explanation:

not really sure

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a