Given the lists, lst1 and lst2, create a new sorted list consisting of all the elements of lst1 that also appears in lst2. For example, if lst1 is [4, 3, 2, 6, 2] and lst2 is [1, 2, 4], then the new list would be [2, 2, 4]. Note that duplicate elements in lst1 that appear in lst2 are also duplicated in the new list. Associate the new list with the variable new_list, and don't forget to sort the new list.

lst1 = [4, 3, 2, 6, 2]

lst2 = [1, 2, 4]

new_lst =  []

for i in lst1:

      if i in lst2:

           new_lst.append(i)

new_lst.sort()

print(new_lst)

Step-by-step explanation:

The code is written in python.

lst1 = [4, 3, 2, 6, 2]

The variable lst1 represent a list of integers.

lst2 = [1, 2, 4]

The variable lst2 represent a list of integers.

new_lst =  []

An empty variable is created new_lst and it is used to store the values of lst1 that is in lst2.

for i in lst1:

The code loop through integers in lst1.

if i in lst2:

This code means if any of the value in lst1 is in lst2.

new_lst.append(i)

This code put the same values found in lst1 and lst2 in a new list(new_lst)

new_lst.sort()

We sort the value of the new list from the smallest to the biggest.

print(new_lst)

The new list is displayed

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: