There are 5 traffic signals between your home and work. Each is red with probability 0.35 , independently of all others. Find: a) the probability of encountering no red lights, 2.26% 5.2% 11.6% 17.5% unanswered b) the probability of encountaring only red lights, 0.03% 0.52% 1.16% 16.4% unanswered c) the expected number of red lights you will encounter? 0.75 1.42 1.75 2.25 unanswered SubmitYou have used 0 of 4 attemptsSome problems have options such as save, reset, hints, or show answer. These options follow the Submit button.

a) 11.6%

b) 0.52%

c) 1.75

Step-by-step explanation:

For each light, there are only two possible outcomes. Either it is red, or it is not. The probability of a light being red is independent from other lights. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

There are 5 traffic signals between your home and work.

This means that

Each is red with probability 0.35

This means that

a) the probability of encountering no red lights

This is P(X = 0). So

So the answer for a is 11.6%

b) the probability of encountaring only red lights

This is P(X = 5)

So the answer for b is 0.52%.

c) the expected number of red lights you will encounter?

The expeced number of the binomial distribution is given by:

So

wheres graph

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1