Four diners have ordered a platter of desserts. The platter holds 8 chocolate chip cookies and 4 slices of chocolate cheesecake. The waiter gives each diner a randomly selected dessert. Let Y = the number of slices of cheesecake left on the platter after the first serving. The distribution of Y is Y 0 1 2 3 4 P(Y) 0.005 0.114 0.429 0.381 0.071 Find the probability that there's more than one slice left, but not all of them are left, i. e.,

And we can find this probability like this:

And we can replace the values and we got:

Step-by-step explanation:

For this case we define the random variable Y as: the number of slices of cheesecake left on the platter after the first serving. And we have the following distribution for Y:

Y     |     0          1        2         3         4

P(Y) | 0.005  0.114  0.429  0.381  0.071

And we want to find the following probability:

And we can find this probability like this:

And we can replace the values and we got:

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.