There are 98 balls in a box. 25 of them are red, 19 of them are green, 30 of them are purple, and 24 of them are blue. Suppose Hao draws 22 balls from the box with replacement (hedraws the ball, records its color, and then puts it back into the box). Find the probabilitythat he draws 2 red balls, 5 green balls, 10 purple balls, and 5 blue balls.

Since the balls are drawn with replacement, it means the individual probability  remain constant,

I have solved this problem on paper (Figures Attached).

Thanks.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.