Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′?

it would be 6xy and -16xy.

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130