A lock consists of 3 dials, where each dial has 4 letters. What is the probability of guessing the right combination in one try?
A.1/7
B.1/12
C.1/24
D.1/64

About 8% of the U. S. population catches the flu each season. Assuming everyone has equal probability of catching the flu, about what are the odds of catching the flu in a given season?

A.1 in 8
B.1 in 12
C.1 in 18
D.1 in 80

Kay has an 80% probability of making a free-throw in basketball, and each free-throw is independent. Kay gets to take 2 free-throws, and must make both to win the game. What is the probability that Kay's team will win the game?

A.64%
B.80%
C.88%
D.160% (so 100%)

D.1/64

B.1 in 12

A.64%

Step-by-step explanation:

Each dial has 4 letters and only one of them is correct; the probability to choose the correct one is then 1/4. Selecting a letter in each dial is independent, then the probability of guessing the right combination in one try is 1/4 * 1/4 * 1/4 = 1/64

8% means a probability of 8/100 or an odds of 8 in 100. Dividing each term by 8 we get 8/8 = 1 in 100/8 = 12.5, which can be rounded to 1 in 12

80% means a probability of 80/100 = 0.8. Given that the 2 free-throws are independent, the probability that he makes both is 0.8*0.8 = 0.64 or 64%

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0