Mel Cheek is a fishing guide on the Chenega River. The fish are usually found 20 to 50 miles upriver. Once the fish are located, Mel slows the boat to trolling speed and fishes for about 6 hours before returning to dock. Mel has noted that overall fuel costs vary based on "miles upriver" and he is considering changing his guide fee to separately charge customers for estimated fuel costs. Below is Mel's log for 15 typical days showing "miles upriver to locate fish" and "total fuel cost".

Day Miles Upriver Fuel Cost
1 37 $86
2 41 93
3 22 73
4 28 80
5 49 99
6 25 74
7 33 85
8 37 87
9 44 93
10 24 77
11 29 80
12 45 96
13 35 83
14 36 87
15 31 80
Total 516 $1,273
(a) Use the high-low method to determine the "fixed fuel cost" associated with the trolling time, and the "variable fuel cost" associated with running up and down the river.
(b) If the sole objective of the fuel charge is to approximately recover actual costs incurred each day, would "$2.50 per mile upriver" be a fair formula? What alternative formula might you suggest?

$(52+1m)

Where m= number of miles upriver

Step-by-step explanation:

Highest Mile Run=49

Lowest Mile Run=22

Difference=49-22=27

Cost at Highest Mile Run =$99

Cost at Lowest Mile Run=$73

Difference=99-73= $26

Variable Cost Per mile upriver

= $26/27 miles =$0.963 per miles

At the highest mile run,

Fixed cost = Total High Cost- Variable Cost

=99-(0.963 X 49)=99-47.19 =$51.81

At the highest mile run,

Fixed cost = Total High Cost- Variable Cost

=73-(0.963 X 22)=73-21.19 =$51.81

(b)Although the idea of charging $2.50 per miles would seem to average out about right (1273/516=$2.48), it would not be a fair price as some days would be overpriced (e.g. 49 miles at $2.50 per mile =$122.5 which is more than expected actual cost) and other days would be underpriced (e.g. 22 miles at $2.50 per mile =$55 which is less than expected actual cost).

A fair formula will be to charge a flat fee of $52 and a cost of $1 per mile upriver.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

christopher is 272,195 year old

step-by-step explanation: