Use algebraic strategies to solve √2x+3=x . How many solutions did you come up with? Which strategies did you use?

x=-1, 3

2 solutions, strategies=quadratic formula

Step-by-step explanation:

1. square the whole equation

(√2x+3)²=(x)²

2x+3=x²

since it becomes a quadratic equation, take all terms on one side = to 0

x²-2x-3=0

Use the quadratic formula, because the equation cannot be factored.

x=(-b±√b²-4ac)/2a

x=(-(-2)±√4-4×1×-3)/2×1

x=(2±√4+12)/2

x=(2±√16)/2

x=(2±4)/2

x=1±2

x=1+2, 1-2

∴x=-1, 3

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.