Mr. Walden wrote the expression StartFraction p Superscript negative 5 Over q Superscript 0 EndFraction. He asked his students to write an equivalent expression of StartFraction p Superscript negative 5 Over q Superscript 0 EndFractionin simplified form. Four students wrote these expressions. Isaac Rosa Bruce Brianna StartFraction q Superscript 0 Over p Superscript negative 5 EndFraction p Superscript negative 5 + q Superscript 0 p Superscript 5 Baseline q Superscript 0 StartFraction 1 Over p Superscript 5 Baseline q Superscript 0 EndFraction Which student is correct? Isaac Rosa Bruce Brianna

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation:

the answer to your question is minor arc.

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem,

in this case, a=b since isocolese triangle so we get

or

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

and

intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough